25(a^2+1)=5(a+5)

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Solution for 25(a^2+1)=5(a+5) equation:


Simplifying
25(a2 + 1) = 5(a + 5)

Reorder the terms:
25(1 + a2) = 5(a + 5)
(1 * 25 + a2 * 25) = 5(a + 5)
(25 + 25a2) = 5(a + 5)

Reorder the terms:
25 + 25a2 = 5(5 + a)
25 + 25a2 = (5 * 5 + a * 5)
25 + 25a2 = (25 + 5a)

Add '-25' to each side of the equation.
25 + -25 + 25a2 = 25 + -25 + 5a

Combine like terms: 25 + -25 = 0
0 + 25a2 = 25 + -25 + 5a
25a2 = 25 + -25 + 5a

Combine like terms: 25 + -25 = 0
25a2 = 0 + 5a
25a2 = 5a

Solving
25a2 = 5a

Solving for variable 'a'.

Reorder the terms:
-5a + 25a2 = 5a + -5a

Combine like terms: 5a + -5a = 0
-5a + 25a2 = 0

Factor out the Greatest Common Factor (GCF), '5a'.
5a(-1 + 5a) = 0

Ignore the factor 5.

Subproblem 1

Set the factor 'a' equal to zero and attempt to solve: Simplifying a = 0 Solving a = 0 Move all terms containing a to the left, all other terms to the right. Simplifying a = 0

Subproblem 2

Set the factor '(-1 + 5a)' equal to zero and attempt to solve: Simplifying -1 + 5a = 0 Solving -1 + 5a = 0 Move all terms containing a to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + 5a = 0 + 1 Combine like terms: -1 + 1 = 0 0 + 5a = 0 + 1 5a = 0 + 1 Combine like terms: 0 + 1 = 1 5a = 1 Divide each side by '5'. a = 0.2 Simplifying a = 0.2

Solution

a = {0, 0.2}

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